document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008661>Question 1008661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find two numbers whose sum is 54, given that one is more than twice the others<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624306 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624306\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call them x and y.  Then we have<BR>\n" );
document.write( "x + y = 54  and<BR>\n" );
document.write( "x = 2y<BR>\n" );
document.write( "Substituting we get<BR>\n" );
document.write( "2y + y = 54<BR>\n" );
document.write( "3y = 54<BR>\n" );
document.write( "y = 18<BR>\n" );
document.write( "and then<BR>\n" );
document.write( "x = 36 </SPAN>\n" );
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