document.write( "Question 1008638: z varies jointly as the square root of the product of x and y. If z is equal to 3 when x is equal to 3 and y is equal to 12,find x when z is equal to 6 and y is equal to 64. \n" ); document.write( "

Algebra.Com's Answer #624303 by fractalier(6550) $\"\"$ $\"About$

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We write this is as
\n" ); document.write( " $\"z+=+k%2Asqrt%28xy%29\"$
\n" ); document.write( "Then we plug in to get
\n" ); document.write( " $\"3+=+k%2Asqrt%283%2A12%29\"$
\n" ); document.write( " $\"3+=+6k\"$
\n" ); document.write( " $\"k+=+1%2F2\"$
\n" ); document.write( "and we have
\n" ); document.write( " $\"z+=+%281%2F2%29%2Asqrt%28xy%29\"$
\n" ); document.write( "Then
\n" ); document.write( " $\"6+=+%281%2F2%29%2Asqrt%2864x%29\"$
\n" ); document.write( " $\"6+=+4%2Asqrt%28x%29\"$
\n" ); document.write( " $\"3%2F2+=+sqrt%28x%29\"$
\n" ); document.write( "and
\n" ); document.write( " $\"x+=+9%2F4\"$
\n" ); document.write( " \n" ); document.write( "

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