document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008705>Question 1008705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The total profit fore Timez series VI watches is given by R(x)=1500x-0.02x^2 where c is the number of watches sold. Determine maximum possible revenue and how many watches must be sold to achieve that profit </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624284 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total profit for Timez series VI watches is given by R(x)=1500x-0.02x^2 where x is the number of watches sold. Determine maximum possible revenue and how many watches must be sold to achieve that profit <BR>\n" );
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document.write( "R(x)=1500x-0.02x^2<BR>\n" );
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document.write( "max occurs when x = -b/(2a) = -1500/(2*-0.02) =  1500/0.04 = 150000/4 = 37500<BR>\n" );
document.write( "max revenue = f(37500) = $2.81x10^7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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