document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008663>Question 1008663</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 40 cm. Four times the length is 3 cm more than 7 times the width. Find the dimension of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624282 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the statements in the problem we have<BR>\n" );
document.write( "P = 2L + 2W = 40  and<BR>\n" );
document.write( "4L = 7W + 3 or 2L = (7/2)W + 3/2<BR>\n" );
document.write( "Substitute this into the first equations and get<BR>\n" );
document.write( "(7/2)(W) + 3/2 + 2W = 40<BR>\n" );
document.write( "(11/2)W = 77/2<BR>\n" );
document.write( "Multiply by two<BR>\n" );
document.write( "11W = 77<BR>\n" );
document.write( "Divide by 11<BR>\n" );
document.write( "W = 7 cm<BR>\n" );
document.write( "L = 13 cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );