document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86252>Question 86252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Knox Valley investment club invested $9000 at 7.8% annual simple interest. How much additional money should they invest at an annual simple interest rate of 5.1%, so that the total annual interest earned from the two accounts is 5.9% of the total investment? <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62425 by </B><A HREF=/tutors/aboutme.mpl?userid=scianci><B>scianci(186)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scianci><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Interest = (Principal)(rate)(time), or I = Prt [r as a decimal, not a percent] <BR>\n" );
document.write( "We have two accounts involved here ; one with a rate of 7.8% [change it to its decimal equivalent] and a principal of $9000 and another with a rate of 5.1% [change it to its decimal equivalent] and a principal of x. Set up an equation: Prt + Prt = Prt, where the first Prt is for the 7.8% account, the second Prt is for the 5.1% account and the last Prt is for the combined interest, which has to be 5.1% [changed to its decimal equivalent] of the total investment (which is x + 9000). Plug in each parameter and solve for x. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );