document.write( "Question 1008650: The sum of the digits of a three-digit number is 11. The tens digit is three times the Hundreds digit and twice the units digit. Find the original number.\r
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document.write( "Help! I don't really know on how to do this.. ._. \n" );
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Algebra.Com's Answer #624237 by maxitee(11)![]() ![]() ![]() You can put this solution on YOUR website! Let's take the digits in the number to be A B and C. \n" ); document.write( " From the question, \n" ); document.write( " A + B + C = 11\r \n" ); document.write( "\n" ); document.write( "A=> Hundreds, \n" ); document.write( "B=> Tens \n" ); document.write( "C= Units.\r \n" ); document.write( "\n" ); document.write( " B = 3A ( tens digit is three times the hundreds digit.. As in the question) \n" ); document.write( " B = 2C (tens digit is twice the unit digit.. As in the question)\r \n" ); document.write( "\n" ); document.write( " This therefore means that 3A = 2C = B. \n" ); document.write( "To relate all elements together, we have. \n" ); document.write( "C = 3A/2 \n" ); document.write( "A= 2C/3 \n" ); document.write( "B= 3A or B = 2C.\r \n" ); document.write( "\n" ); document.write( " From the first equation, (A+B+C=11) \n" ); document.write( "If we substitute the values of B and C in terms of A, we have the following;\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If A = 2, Then B = 6, Making C = 3.\r \n" ); document.write( "\n" ); document.write( " The original number is 263\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(Engr. Terry, Nigeria) \n" ); document.write( " |