document.write( "Question 1008600: A petroleum company has two different sources of crude oil. the first source provides crude oil that is 25% hydrocarbons and the second one provides crude oil that is 50% hydrocarbons. In order to obtain 60 gallons of crude oil that is 30% hydrocarbons how many gallons of crude oil must be used from each of the two sources\r
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Algebra.Com's Answer #624200 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A petroleum company has two different sources of crude oil. the first source provides crude oil that is 25% hydrocarbons and the second one provides crude oil that is 50% hydrocarbons. In order to obtain 60 gallons of crude oil that is 30% hydrocarbons how many gallons of crude oil must be used from each of the two sources \n" ); document.write( "----- \n" ); document.write( "Using 2 equations:: \n" ); document.write( "Quantity:: t + f = 60 gallons \n" ); document.write( "Oil equations: 0.25t + 0.50f = 0.30*60 oil \n" ); document.write( "-------- \n" ); document.write( "Modify for eliminations:: \n" ); document.write( "25t + 25f = 25*60 \n" ); document.write( "25t + 50f = 30*60 \n" ); document.write( "--------------------- \n" ); document.write( "Subtract and solve for \"f\":: \n" ); document.write( "25f = 5*60 \n" ); document.write( "f = 12 gallons (amt. of 50% hydro needed) \n" ); document.write( "t = 60-12 = 48 gallons (amt. of 25% hydro needed) \n" ); document.write( "------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "first source = \n" ); document.write( "Second source = \n" ); document.write( " |