document.write( "Question 1008417: A IS three time old as b .C was twice as old as A four year ago .in four year time A will 31. What the present age B and C? \n" ); document.write( "
Algebra.Com's Answer #624198 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Write an equation for each statement \n" ); document.write( ": \n" ); document.write( "A IS three time old as B \n" ); document.write( "A = 3B \n" ); document.write( "; \n" ); document.write( "C was twice as old as A four year ago \n" ); document.write( "C -4 = 2(A-4) \n" ); document.write( ": \n" ); document.write( "in four year time A will 31. \n" ); document.write( "A + 4 = 31 \n" ); document.write( "A =31- 4 \n" ); document.write( "A = 27 yrs, his present age \n" ); document.write( ": \n" ); document.write( "Then using the 2nd equation \n" ); document.write( "c - 4 = 2(27 - 4) \n" ); document.write( "C - 4 = 2(23) \n" ); document.write( "c = 46 + 4 \n" ); document.write( "C = 50 yrs, his present age \n" ); document.write( ": \n" ); document.write( "and the 1st equation \n" ); document.write( "27 = 3B \n" ); document.write( "Divide both sides by 3 \n" ); document.write( "9 = B \n" ); document.write( ": \n" ); document.write( " What the present age B and C? \n" ); document.write( "B is 9, C is 50 \n" ); document.write( " |