document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008466>Question 1008466</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this equation:|x-3|+|x-3|=9 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624176 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cases.  Either x-3 is non-negative, or x-3 is negative.  Solve according to both conditions separately.\r<BR>\n" );
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document.write( "This means  <BR>\n" );
document.write( "EITHER<BR>\n" );
document.write( "x-3+x-3=9<BR>\n" );
document.write( "OR<BR>\n" );
document.write( "-(x-3)-(x-3)=9 </SPAN>\n" );
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