document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86315>Question 86315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bicyclist rode into the country for 5 h. In returning , her speed was 5 mi/h faster and the trip tool 4 h.What washer speed each way? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62414 by </B><A HREF=/tutors/aboutme.mpl?userid=scianci><B>scianci(186)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scianci><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62414\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> distance = (rate)(time)<BR>\n" );
document.write( "her distance is the same coming and going<BR>\n" );
document.write( "(rate)(time) for the trip out = (rate)(time) for the trip back<BR>\n" );
document.write( "5x = 4(x + 5)<BR>\n" );
document.write( "5x = 4x + 20<BR>\n" );
document.write( "5x - 4x = 20<BR>\n" );
document.write( "x = 20 MPH on the trip out<BR>\n" );
document.write( "x + 5 = 20 + 5 = 25 MPH on the trip back </SPAN>\n" );
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