document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008377>Question 1008377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find standard equation of circle that has centre on the line 5x-2y= -21 and tangent to both co-ordinate axes<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #624100 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=624100\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> STRATEGY:  The equivalent linear equation, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%285%2F2%29x%2B10%261%2F2 ALIGN=MIDDLE  ALT=\"y=%285%2F2%29x%2B10%261%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > must be an equal distance from x-axis, (x,0) as from y-axis, (0,y), because the point on each axis this equal distance is a point of tangency ON EACH of the axes.\r<BR>\n" );
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document.write( "Distance from the center (x, (5/2)x+21/2 )  to x-axis and to y-axis must be equal, because each axis contains a tangency point.  Use distance formula.\r<BR>\n" );
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document.write( "That is a described strategy, but not the actual solution. </SPAN>\n" );
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