document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12304>Question 12304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a triangle is 76cm. side A of the triangle istwo times the length of side B. side C is one cm more than side A. what is the lengths of the sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6241 by </B><A HREF=/tutors/aboutme.mpl?userid=askmemath><B>askmemath(368)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=askmemath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimemter = Sum of the 3 sides<BR>\n" );
document.write( "Let side B = s<BR>\n" );
document.write( "Side A = 2Times B = 2xs = 2s<BR>\n" );
document.write( "Side C is 1 more than A = 2s+1\r<BR>\n" );
document.write( "\n" );
document.write( "Sum = s+2s+2s+1=76<BR>\n" );
document.write( "5s+1=76<BR>\n" );
document.write( "5s=75     Subtracting 1 on both sides<BR>\n" );
document.write( "s=15<BR>\n" );
document.write( "i.e B = 15cms<BR>\n" );
document.write( "A= 2x15 = 30cms<BR>\n" );
document.write( "C = 30+1 = 31cms </SPAN>\n" );
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