document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=86312>Question 86312</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #62407 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=62407\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the length of a rectangle is 2 cm more than twice its width. If the perimeter of the rectangle is 52 cm, find the dimensions of the rectangle.<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Let the width be \"x\" cm; length = \"2x+2\" cm.<BR>\n" );
document.write( "Perimeter = 2(length + width)<BR>\n" );
document.write( "52 = 2(2x+2+x)<BR>\n" );
document.write( "26 = 3x+2<BR>\n" );
document.write( "3x = 24<BR>\n" );
document.write( "x = 8 cm (width)<BR>\n" );
document.write( "x+2 = 10 cm (length)<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );