document.write( "Question 1008271: Hello, Please help!! :)\r
\n" ); document.write( "\n" ); document.write( "Laura burrows $6250 at a rate of 9% compounded monthly. Find how much Laura owes at the end of 3 years. Use...\r
\n" ); document.write( "\n" ); document.write( "A=P(1+R/N)^nt\r
\n" ); document.write( "\n" ); document.write( "Round to two decimal places.\r
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\n" ); document.write( "\n" ); document.write( "THANK YOU!!
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Algebra.Com's Answer #624047 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "$\"A\" = final amount
\n" ); document.write( "$\"P+=+6250\" (the amount borrowed)
\n" ); document.write( "\"r+=+9\"% or \"r=+0.09\" (the annual rate of interest)
\n" ); document.write( "\"n+=+12\" (the number of times interest is compounded each year, monthly)
\n" ); document.write( "\"t+=+3\" (the duration of the loan in years)\r
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\n" ); document.write( "\n" ); document.write( "\"A=P%281%2BR%2FN%29%5E%28nt%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=6250%281%2B0.09%2F12%29%5E%2812%2A3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=6250%281%2B0.0075%29%5E%2836%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=6250%281.0075%29%5E%2836%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=6250%281.3086453709165336437514553%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=8179.033568228335273446595625\"\r
\n" ); document.write( "\n" ); document.write( "$\"A=8179.03\"\r
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