document.write( "Question 1008299: Solve:\r
\n" ); document.write( "\n" ); document.write( "y-1 = sqrt 2y-2
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Algebra.Com's Answer #624041 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
y-1 = sqrt (2y-2)
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\n" ); document.write( "(y-1)^2 = 2y-2
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\n" ); document.write( "y^2 -2y + 1 = 2y - 2
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\n" ); document.write( "y^2 - 4y + 3 = 0
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\n" ); document.write( "Factor::
\n" ); document.write( "(y-1)(y-3) = 0
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\n" ); document.write( "y = 1 or y = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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