document.write( "Question 1008197: Maria plans to invest a total of $7500 between two types of stocks, one yielding 6% interest and the other 15%. How much does she invest in each type of stock if the total interest gained annually is $585? \n" ); document.write( "
Algebra.Com's Answer #623993 by ankor@dixie-net.com(22740)\"\" \"About 
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Maria plans to invest a total of $7500 between two types of stocks, one yielding 6% interest and the other 15%.
\n" ); document.write( " How much does she invest in each type of stock if the total interest gained annually is $585?
\n" ); document.write( ":
\n" ); document.write( " let x = amt invested at 15%
\n" ); document.write( "The total investment is $7500, therefore:
\n" ); document.write( "(7500-x) = amt invested at 6%
\n" ); document.write( ":
\n" ); document.write( ".06(7500-x) + .15x = 585
\n" ); document.write( "450 - .06x + .15x = 585
\n" ); document.write( "-.06x + .15x = 585 - 450
\n" ); document.write( ".09x = 135
\n" ); document.write( "x = 135/.09
\n" ); document.write( "x = $1500 invested at 15%
\n" ); document.write( "then
\n" ); document.write( "7500 - 1500 = $6000 invested at 6%
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the actual interest from each investment
\n" ); document.write( ".06*6000 = $360
\n" ); document.write( ".15*1500 - $225
\n" ); document.write( "--------------------
\n" ); document.write( "total int: $585
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