document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008121>Question 1008121</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the area and perimeter of a ice cream cone shape object when the width given is 6m and the length given is 6m?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623980 by </B><A HREF=/tutors/aboutme.mpl?userid=Master+Singleton><B>Master Singleton(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Master+Singleton><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So your question \"what is the area and perimeter of a ice cream cone shape object when the width given is 6m and the length given is 6m?\" is a bit vague but from my perspective do you mean \"the width given\" as \"the diameter given\" of the semi-circle and as \"the base of the triangle given\" is 6 meters and \"the height given\" as \"the height given\" of the triangle is 6 meters? Also do you mean this shape shown below? \r<BR>\n" );
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document.write( "If yes then to find the area of a semi-circle: \r<BR>\n" );
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document.write( "Firstly find the radius of the semi-circle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+radius+=+0.5%2A6+=+3+ ALIGN=MIDDLE  ALT=\"+radius+=+0.5%2A6+=+3+\"   DISABLED_style= \"max-width:90%; height:auto;\" > then sub 3 into the area of semi-circle formula <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=%280.5%2Api%29%2Aradius%5E2+ ALIGN=MIDDLE  ALT=\"+A+=%280.5%2Api%29%2Aradius%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which looks like this <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=%280.5%2Api%29%2A3%5E2+ ALIGN=MIDDLE  ALT=\"+A+=%280.5%2Api%29%2A3%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which then equates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+1.570796327%2A9+ ALIGN=MIDDLE  ALT=\"+1.570796327%2A9+\"   DISABLED_style= \"max-width:90%; height:auto;\" > and finally <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=+14.13716694m%5E2+ ALIGN=MIDDLE  ALT=\"+A+=+14.13716694m%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Then to find the area of a triangle: \r<BR>\n" );
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document.write( "Firstly sub both 6's into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=+%280.5%2Abase%29%2Aheight+ ALIGN=MIDDLE  ALT=\"+A+=+%280.5%2Abase%29%2Aheight+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which looks like this <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=+%280.5%2A6%29%2A6+ ALIGN=MIDDLE  ALT=\"+A+=+%280.5%2A6%29%2A6+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which equates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+3%2A6+ ALIGN=MIDDLE  ALT=\"+3%2A6+\"   DISABLED_style= \"max-width:90%; height:auto;\" > and finally <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=18m%5E2+ ALIGN=MIDDLE  ALT=\"+A+=18m%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "Then find the sum of the area of a triangle and the area of a semi-circle:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=+14.13716694m%5E2+%2B+18m%5E2+ ALIGN=MIDDLE  ALT=\"+A+=+14.13716694m%5E2+%2B+18m%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which equates to  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+A+=+32.13716694m%5E2+ ALIGN=MIDDLE  ALT=\"+A+=+32.13716694m%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "To find the perimeter first find the hypotenuse of the triangle:\r<BR>\n" );
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document.write( "first sub 3 and 6 into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Hypotenuse%5E2+=+base%5E2%2Bheight%5E2+ ALIGN=MIDDLE  ALT=\"+Hypotenuse%5E2+=+base%5E2%2Bheight%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which looks like this <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Hypotenuse%5E2+=+3%5E2%2B6%5E2+ ALIGN=MIDDLE  ALT=\"+Hypotenuse%5E2+=+3%5E2%2B6%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which equates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Hypotenuse+=+sqrt%2845%29+ ALIGN=MIDDLE  ALT=\"+Hypotenuse+=+sqrt%2845%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > and finally <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Hypotenuse+=+6.708203932m+ ALIGN=MIDDLE  ALT=\"+Hypotenuse+=+6.708203932m+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "secondly find the arc of the semi-circle: \r<BR>\n" );
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document.write( "first sub 6 into <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Arc++=+%280.5pi%29%2Adiameter+ ALIGN=MIDDLE  ALT=\"+Arc++=+%280.5pi%29%2Adiameter+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which looks like this <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Arc++=+%280.5pi%29%2A6+ ALIGN=MIDDLE  ALT=\"+Arc++=+%280.5pi%29%2A6+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which equates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Arc++=+1.570796327%2A6+ ALIGN=MIDDLE  ALT=\"+Arc++=+1.570796327%2A6+\"   DISABLED_style= \"max-width:90%; height:auto;\" > and finally <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+Arc++=+9.424777961m+ ALIGN=MIDDLE  ALT=\"+Arc++=+9.424777961m+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "finally find the sum of the hypotenuses and the arc of the semi-circle to find the perimeter:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+P++=+%286.708203932%2A2%29%2B9.424777961+ ALIGN=MIDDLE  ALT=\"+P++=+%286.708203932%2A2%29%2B9.424777961+\"   DISABLED_style= \"max-width:90%; height:auto;\" > which equates to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+P+=+22.84118582m+ ALIGN=MIDDLE  ALT=\"+P+=+22.84118582m+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Therefore the area of the cone is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+32.13716694m%5E2+ ALIGN=MIDDLE  ALT=\"+32.13716694m%5E2+\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the perimeter of the cone is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+22.84118582m+ ALIGN=MIDDLE  ALT=\"+22.84118582m+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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