document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008068>Question 1008068</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a triangle is 30 inches. the first side of the triangle is 1 inch longer than the second side. the second side is 7 inches longer than the third side. what is the length of each side of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623910 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the sides a, b and c.  Then we have<BR>\n" );
document.write( "a + b + c = 30<BR>\n" );
document.write( "a = b + 1<BR>\n" );
document.write( "b = c + 7  or  c = b - 7<BR>\n" );
document.write( "Now substitute into the first equation and get<BR>\n" );
document.write( "b+1 + b + b-7 = 30<BR>\n" );
document.write( "3b - 6 = 30<BR>\n" );
document.write( "3b = 36<BR>\n" );
document.write( "b = 12  so that<BR>\n" );
document.write( "a = 13<BR>\n" );
document.write( "c = 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );