document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008075>Question 1008075</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to a rating survey, 58% of the households in a certain city tune in to the local evening TV news. If ten households are visited at random, what is the probability that three of them will have their television tuned to the local news? (Round answer to five decimal places.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623891 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10C3(0.58)^3(0.42)^7.  This looks at all possible combinations of 3 houses chosen from 10.<BR>\n" );
document.write( "120*(0.58)^3(0.42)^7=0.05398<BR>\n" );
document.write( "The expected value is nearly 6, so one would expect a low probability of finding only 3. </SPAN>\n" );
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