document.write( "Question 1008112: what is the sum of all integer values of x such that 31/90 < x/100 < 41/110 is true?\r
\n" ); document.write( "\n" ); document.write( "The answer is 108. How?
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Algebra.Com's Answer #623883 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\"31%2F90+%3C+x%2F100+%3C+41%2F110\".............all terms multiply by \"100\"\r
\n" ); document.write( "\n" ); document.write( "\"%28100%2A31%29%2F90+%3C+100x%2F+100%3C+%28100%2A41%29%2F110\"\r
\n" ); document.write( "\n" ); document.write( "\"%2810%2A31%29%2F9+%3C+x%3C+%2810%2A41%29%2F11\"\r
\n" ); document.write( "\n" ); document.write( "\"310%2F9%3Cx%3C410%2F11\"\r
\n" ); document.write( "\n" ); document.write( "\"34%3C+x+%3C+37\"\r
\n" ); document.write( "\n" ); document.write( "between \"34\" and \"37\" (including\"37\") we have :\r
\n" ); document.write( "\n" ); document.write( "\"35\",\"36\" and \"37\" and their sum is\r
\n" ); document.write( "\n" ); document.write( "\"35%2B36%2B37=108\"\r
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