document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007988>Question 1007988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How long does it take for an initial investment of $2,500, earning 6.18% interest, compounded continuously, to double? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623820 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623820\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We use the formula for continuously compounded interest,<BR>\n" );
document.write( "A(t) = Ao * e^(rt)<BR>\n" );
document.write( "Plugging in we get<BR>\n" );
document.write( "5000 = 2500 * e^(.0618t)<BR>\n" );
document.write( "and solve for t<BR>\n" );
document.write( "2 = e^(.0618t)<BR>\n" );
document.write( "ln 2 = .0618t<BR>\n" );
document.write( "t = ln 2 / .0618 = 11.2 years </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );