document.write( "Question 1008024: Last year, MAry was three times as old as sha. A year later, she was twice as old as sha. How old are mary and sha? \n" ); document.write( "

Algebra.Com's Answer #623816 by fractalier(6550) $\"\"$ $\"About$

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Call their ages NOW, m and s. Last year
\n" ); document.write( "m - 1 = 3(s - 1)
\n" ); document.write( "A year later would be this year, so
\n" ); document.write( "m = 2s
\n" ); document.write( "Substituting we get
\n" ); document.write( "2s - 1 = 3(s - 1)
\n" ); document.write( "2s - 1 = 3s - 3
\n" ); document.write( "Now subtract 2s and add 3 and get
\n" ); document.write( "-1 = s - 3
\n" ); document.write( "2 = s
\n" ); document.write( "m = 4 \n" ); document.write( "

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