document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008032>Question 1008032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a hollow sphere sits snugly in a foam cube so that the sphere touches each side of the cube. find the volume of the foam </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623809 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623809\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of the foam would be the volume of the cube minus the volume of the sphere...say the sphere has a radius of r, then the cube has a side of 2r...then we have<BR>\n" );
document.write( "V(foam) = V(cube) - V(sphere)<BR>\n" );
document.write( "V(foam) = (2r)^3 - (4/3)(pi)r^3<BR>\n" );
document.write( "V(foam) = 8r^3 - (4/3)(pi)r^3<BR>\n" );
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