document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1008018>Question 1008018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please solve me this question i need help\r<BR>\n" );
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document.write( "the sum of three consecutive numbers is 60 find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623803 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the first number.<BR>\n" );
document.write( "x + 1 is the second number.<BR>\n" );
document.write( "x + 2 is the third number.\r<BR>\n" );
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document.write( "3x + 3 = 60<BR>\n" );
document.write( "subtract 3 from both sides of that equation to get:<BR>\n" );
document.write( "3x = 57<BR>\n" );
document.write( "divide both sides of that equation by 3 to get;<BR>\n" );
document.write( "x = 19.\r<BR>\n" );
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document.write( "the numbers are 19, 20, 21<BR>\n" );
document.write( "add them up and you get 60.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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