document.write( "Question 86285: Hello:
\n" ); document.write( "I am in a pre ca class and have a problem I just do not understand how to work. Math is not my best skill anyway. i am lost.
\n" ); document.write( "Here it is
\n" ); document.write( "sq root sign and under it is x^2 - 10x + 28 = 2. the =2 is not under the sq. root sign.\r
\n" ); document.write( "\n" ); document.write( "Can you work this for me where I can understand the steps. I am very poor at factoring.
\n" ); document.write( "Thank you
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Algebra.Com's Answer #62380 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
sq root sign and under it is x^2 - 10x + 28 = 2. the =2 is not under the sq. root sign.
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\n" ); document.write( "\"sqrt%28x%5E2+-+10x+%2B+28%29\" = 2
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\n" ); document.write( "Square both sides of the equation and you have:
\n" ); document.write( "x^2 - 10x + 28 = 4
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\n" ); document.write( "x^2 - 10x + 28 - 4 = 0; subtract 4 from both sides
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\n" ); document.write( "x^2 - 10x + 24 = 0
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\n" ); document.write( "Easily factored; look for two factors of 24 which add up to -10: -4 and -6
\n" ); document.write( "(x - 4)(x - 6) = 0
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\n" ); document.write( "x = +4
\n" ); document.write( "and
\n" ); document.write( "x = +6
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\n" ); document.write( "You can check your solutions by substituting 4 for x in the original eq:
\n" ); document.write( "\"sqrt%284%5E2+-+10%284%29+%2B+28%29\" = 2
\n" ); document.write( "\"sqrt%2816+-+40+%2B+28%29\" = 2
\n" ); document.write( "\"sqrt%284%29\" = 2
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\n" ); document.write( "Do the same with x = 6
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\n" ); document.write( "Did this help?
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