document.write( "Question 1007986: A plane travels at a speed of 190 mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 2 hours longer to complete the return trip. What was the wind velocity? (Round your answer to the nearest tenth.) \n" ); document.write( "
Algebra.Com's Answer #623768 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A plane travels at a speed of 190 mph in still air. Flying with a tailwind, the plane is clocked over a distance of 950 miles. Flying against a headwind, it takes 2 hours longer to complete the return trip. What was the wind velocity? (Round your answer to the nearest tenth.) \n" ); document.write( "------ \n" ); document.write( "With wind DATA: \n" ); document.write( "rate = 190+w mph ; distance = 950 miles ; time = d/r = 950/(190+w) hrs \n" ); document.write( "--- \n" ); document.write( "Against wind DATA: \n" ); document.write( "rate = 190-w mph ; distance = 950 miles ; time = 950/(190-w) hrs \n" ); document.write( "---- \n" ); document.write( "Equation: \n" ); document.write( "against - with = 2 hrs \n" ); document.write( "---- \n" ); document.write( "950/(190-w) - 950/(190+w) = 2 \n" ); document.write( "------ \n" ); document.write( "950(190+w) - 950(190-w) = 2(190^2-w^2) \n" ); document.write( "---- \n" ); document.write( "2(950w) = 2(190^2-w^2) \n" ); document.write( "---- \n" ); document.write( "w^2 + 950w - 190^2 = 0 \n" ); document.write( "----- \n" ); document.write( "wind = 36.59 mph \n" ); document.write( "---------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------------- \n" ); document.write( " |