document.write( "Question 1007977: The relation d=0.0052s^2 + 0.13s models the stopping distance, d, in metres, of a car travelling at a speed of s, in kilometres per hour, when the driver breaks hard. At what speed was a car travelling if its stopping distance is 20m? Round to the nearest tenth. \n" ); document.write( "
Algebra.Com's Answer #623765 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "we are given \"d=0.0052s%5E2+%2B+0.13s\", and \"d=20m\"
\n" ); document.write( "the equation becomes
\n" ); document.write( "\"0.0052s%5E2+%2B+0.13s+-+20+=+0\" and we will use the following quadratic formula to solve it for \"s\",\r
\n" ); document.write( "\n" ); document.write( "\"s+=+%28-0.13+%2B-+sqrt%280.13%5E2+-+4%2A0.0052%2A%28-20%29%29%29+%2F+%282%2A0.0052%29\" \r
\n" ); document.write( "\n" ); document.write( "\"s+=+%28-0.13+%2B-+sqrt%280.0169+%2B+0.416%29%29+%2F0.0104\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"s+=+%28-0.13+%2B-+sqrt%280.4329%29%29+%2F0.0104\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=+%28-0.13+%2B-+0.6579513659838393%29+%2F0.0104\"\r
\n" ); document.write( "\n" ); document.write( "solutions:
\n" ); document.write( "\"s+=+%28-0.13+%2B+0.6579513659838393%29+%2F0.0104\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=0.5279513659838393%2F0.0104\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=50.76455442152301\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=50.8\"\r
\n" ); document.write( "\n" ); document.write( "or
\n" ); document.write( "\"s+=+%28-0.13+-+0.6579513659838393%29+%2F0.0104\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=-0.7879513659838393%2F0.0104\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=-75.76455442152300961538461\"\r
\n" ); document.write( "\n" ); document.write( "\"s+=-75.8\"...disregard negative solution\r
\n" ); document.write( "\n" ); document.write( "and your solution is:\r
\n" ); document.write( "\n" ); document.write( "\"s=+50.8%28km%2Fh%29\"\r
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