document.write( "Question 1007875: Determine the allowable values for the variable in the expression. Write your answer in interval notation\r
\n" ); document.write( "\n" ); document.write( "(x+6)/(3x-27) \r
\n" ); document.write( "\n" ); document.write( "Do you only solve for the denominator?
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Algebra.Com's Answer #623718 by fractalier(6550)\"\" \"About 
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(x+6)/(3x-27)
\n" ); document.write( "Yes, only the values in the denominator need be considered.
\n" ); document.write( "Thus when 3x - 27 = 0, we have a disallowed value of x...
\n" ); document.write( "3x - 27 = 0
\n" ); document.write( "3x = 27
\n" ); document.write( "x = 9
\n" ); document.write( "In interval notation, we can write
\n" ); document.write( "(-inf, 9) or (9, inf)
\n" ); document.write( "as the allowable values.
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