document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007853>Question 1007853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive term of a G.P  whose sum is 21  and whose product is 64 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623697 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the first term a and the ratio r.  Then our three terms are<BR>\n" );
document.write( "a, ar and ar^2.  The facts in the problem state that<BR>\n" );
document.write( "a + ar + ar^2 = 21  and<BR>\n" );
document.write( "a(ar)(ar^2) = 64<BR>\n" );
document.write( "a^3*r^3 = 64<BR>\n" );
document.write( "(ar)^3 = 64<BR>\n" );
document.write( "ar = 4  (or r = 4/a)<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "a + 4 + ar^2 = 21<BR>\n" );
document.write( "a + ar^2 = 17<BR>\n" );
document.write( "a + a(4/a)^2 = 17<BR>\n" );
document.write( "a + 16/a = 17<BR>\n" );
document.write( "a^2 + 16 = 17a<BR>\n" );
document.write( "a^2 - 17a + 16 = 0<BR>\n" );
document.write( "(a - 16)(a - 1) = 0<BR>\n" );
document.write( "a = 16 or a = 1  so that <BR>\n" );
document.write( "r = 1/4 or r = 4<BR>\n" );
document.write( "and our three terms are<BR>\n" );
document.write( "1, 4, 16 or 16, 4, 1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );