document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007826>Question 1007826</A>: <I><SPAN STYLE=\"word-break: break-all;\"> John's school is selling tickets to a play. On the first day of ticket sales the school sold 10 senior citizen tickets<BR>\n" );
document.write( "and 3 student tickets for a total of $57. The school took in $114 on the second day by selling 5 senior citizen<BR>\n" );
document.write( "tickets and 11 student tickets. What is the price each of one senior citizen ticket and one student ticket? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623687 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the prices of senior and student tickets be x and y.  Then we have<BR>\n" );
document.write( "10x + 3y = 57  and<BR>\n" );
document.write( "5x + 11y = 114<BR>\n" );
document.write( "Now multiply this second equation by two and subtract from the first and we get<BR>\n" );
document.write( "10x + 3y = 57<BR>\n" );
document.write( "-(10x + 22y = 228)<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "-19y = - 171<BR>\n" );
document.write( "y = 9 dollar student tickets<BR>\n" );
document.write( "Substituting back into the first equation gives<BR>\n" );
document.write( "10x + 3(9) = 57<BR>\n" );
document.write( "10x + 27 = 57<BR>\n" );
document.write( "10x = 30<BR>\n" );
document.write( "x = 3 dollar senior tix<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );