document.write( "Question 86258: A researcher orders a broth of 7.5% glucose for her lab. However, she needs a stronger broth, one that is 24.9% glucose. Fortunately, she has 26.9 liters of 36.1% glucose broth in the stock room. How much 24.9% glucose broth can she make? \r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #62368 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let x=amount of 7.5% glucose broth that needs to be added to the 36.1% broth in order to get a 24.9% broth\r \n" ); document.write( "\n" ); document.write( "Then 26.9+x=amount of 24.9% glucose broth that can be made.\r \n" ); document.write( "\n" ); document.write( "Amount of pure glucose in the 7.5% broth is 0.075x \n" ); document.write( "Amount of pure glucose in the 36.1% broth is 0.361(26.9) \n" ); document.write( "Amount of pure glucose in the final broth is 0.249(26.9+x)\r \n" ); document.write( "\n" ); document.write( "pure glucose before = pure glucose after\r \n" ); document.write( "\n" ); document.write( "0.075x+0.361(26.9)=0.249(26.9+x) get rid of parens\r \n" ); document.write( "\n" ); document.write( "0.075x+9.7109=6.6981+0.249x subtract 9.7109 and also 0.249x from both sides\r \n" ); document.write( "\n" ); document.write( "0.075x+9.7109-9.7109-0.249x=6.6981-9.7109+0.249x-0.249x collect like terms\r \n" ); document.write( "\n" ); document.write( "-0.174x=-3.0128 divide both sides by -0.174\r \n" ); document.write( "\n" ); document.write( "x=17.31 --------------------liters of 7.5% broth that's needed\r \n" ); document.write( "\n" ); document.write( "26.9+17.31=44.215-------------------liters of 24.9% broth that can be made\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "0.075(17.31)+0.361(26.9)=0.249(44.215) \n" ); document.write( "1.298+9.7109=11.009 \n" ); document.write( "11.009=11.009\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |