document.write( "Question 1007804: After Exactly 12o'clock in the noon, what time will the hands of a clock be together again ?
\n" ); document.write( "Complete Solution needed as soon as possible .
\n" ); document.write( "Best Regards . . . Ajwad
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #623650 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Well, this one involves an infinite series that is to be added...
\n" ); document.write( "When the minute hand travels 60 minutes, the hour hand travels 5 minutes.
\n" ); document.write( "When the minute hand travels 5 minutes, the hour hand travels (1/12)(5) minutes.
\n" ); document.write( "When the minute hand travels (1/12)(5) minutes, the hour hand travels (1/144)(5) minutes.
\n" ); document.write( "When the minute hand travels (1/144)(5) minutes, the hour hand travels (1/1728)(5) minutes...and so on...\r
\n" ); document.write( "\n" ); document.write( "Thus we can add up the travels of the hour hand as an infinite series,
\n" ); document.write( "\"S+=+a1+%2F+%281+-+r%29\"
\n" ); document.write( "where a1 = 5 and r = 1/12 and we get
\n" ); document.write( "S = 5 / (1 - 1/12) = 5 / (11/12) = 60/11 minutes or 5 5/11 minutes past 1 o'clock.
\n" ); document.write( "
\n" );