document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007811>Question 1007811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (radical 9-2v) = (radical 3v-3) - 2\r<BR>\n" );
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document.write( "I don't know where to begin. I know the answer is 4, but I don't know how to get there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623649 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52782)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623649\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "(radical 9-2v) = (radical 3v-3) - 2\r<BR>\n" );
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document.write( "I don't know where to begin. I know the answer is 4, but I don't know how to get there.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%289-2v%29 ALIGN=MIDDLE  ALT=\"sqrt%289-2v%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283v-3%29 ALIGN=MIDDLE  ALT=\"sqrt%283v-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > - 2.\r<BR>\n" );
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document.write( "Start by squaring both sides.<BR>\n" );
document.write( "Then simplify both sides.<BR>\n" );
document.write( "Then isolate the remaining square root and square both sides again.\r<BR>\n" );
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document.write( "In this way you will get the roots of the equation.\r<BR>\n" );
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document.write( "At the end check that the found roots belong to the domain 9-2v > =0 and 3v-3 >= 0, <BR>\n" );
document.write( "where the square roots of the original equation are defined.\r<BR>\n" );
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