document.write( "Question 86260: How many pounds of salted nuts selling for $3.40 per pound should be mixed with 3 pounds of salted nuts selling for $2.00 per pound to obtain a mixture selling for $2.98 per pound?
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Algebra.Com's Answer #62361 by ptaylor(2198) $\"\"$ $\"About$

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Let x=amount of $3.40 nuts that should be used\r
\n" ); document.write( "\n" ); document.write( "Cost of $3.40 nuts=$3.40x
\n" ); document.write( "Cost of $2.00 nuts=$2.00(3)\r
\n" ); document.write( "\n" ); document.write( "Cost of final mixture=$2.98(3+x)\r
\n" ); document.write( "\n" ); document.write( "Now we know that the cost of the nuts before the mixture ($3.40x+$2.00(3)) must equal the cost of the nuts in the final mixture($2.98(3+x)) so our equation to solve is:\r
\n" ); document.write( "\n" ); document.write( "$3.40x+$2.00(3)=$2.98(3+x) get rid of parens\r
\n" ); document.write( "\n" ); document.write( "$3.40x+$6.00=$8.94+$2.98x subtract $6.00 and also $2.98x from both sides\r
\n" ); document.write( "\n" ); document.write( "$3.40x+6.00-$6.00-$2.98x=$8.94-$6.00+$2.98x-$2.98x collect like terms
\n" ); document.write( "0.42x=$2.94 divide both sides by 0.42\r
\n" ); document.write( "\n" ); document.write( "x=7 lb------amount of $3.40 nuts that must be added\r
\n" ); document.write( "\n" ); document.write( "CK\r
\n" ); document.write( "\n" ); document.write( "$3.40(7)+$2.00(3)=$2.98(10)
\n" ); document.write( "$23.80+$6.00=$29.80
\n" ); document.write( "$29.80=$29.80\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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