Algebra.Com's Answer #623573 by cparks1000000(5)![\"\"](\"/images/stars/iconNewId_16x16.gif\")  
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The solution is not unique. I am assuming that you are only concerned with real coordinates on the plane. Thus we first calculate the length of  \r
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document.write( "Now we know that P = ( x, y ) and thus  .\r
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document.write( "Next we inspect the expression:  . We plug in  and  and multiply by to yield  . Now we square both sides and plug in the expression for  . Thus we get the equation  . Then we subtract 20 to yield  .\r
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document.write( "Now is a tricky part. We have two unknowns  and  and only one equation. Thus there are infinitely many solutions. Thus we can choose to be anything, then solve for . Set  ,  , and  , then our equation simply looks like the standard quadratic  Then we use the quadratic equation to yield  . Here I remark that only positive things can be inside the square root. Thus we must choose such that  implies  implies  . Now we factor the quadratic using the quadratic formula:  . We plug this into the inequality and note that  is a solution to yield that  This implies that has solutions in the set [ ,  ]. \r
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document.write( "One particular solution occurs when x = 0. Thus in this case,  and we can take the positive version of the square root to yield  \r
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document.write( "Check the answer:\r
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document.write( " .\r
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document.write( "Thus  \n" );
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