document.write( "Question 1007701: 3+1/(2-3i) \n" ); document.write( "
Algebra.Com's Answer #623554 by stanbon(75887)\"\" \"About 
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3+1/(2-3i)
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\n" ); document.write( "1/(2-3i) = (2+3i)/(2^2+3^2) = (2+3i)/13 = (2/13) + (3/13)i
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\n" ); document.write( "Therefore:
\n" ); document.write( "Ans:: (3+2/13) + (3/13)i) = (41/13) + (3/13)i
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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