document.write( "Question 1007654: A person rowed their boat downstream for 100 miles and they took 2 hours. Returning upstream, the trip took 2 hours and 40 minutes.\r
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Algebra.Com's Answer #623538 by mananth(16949)\"\" \"About 
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\n" ); document.write( "Boat speed speed =x mph
\n" ); document.write( "stream speed =y mph
\n" ); document.write( "against stream 2 2/3 hours
\n" ); document.write( "with stream 2 hours
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\n" ); document.write( "Distance with stream 100 miles distance against stream 100
\n" ); document.write( "t=d/r against stream (x-y)
\n" ); document.write( "100 / ( x - y )= 2 2/3
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\n" ); document.write( "2 2/3 x - -2 2/3 y = 100 ....................1
\n" ); document.write( "with stream (x+y)
\n" ); document.write( "100 / ( x + y )= 2
\n" ); document.write( "2 ( x + y ) = 100
\n" ); document.write( "2 x + 2 y = 100 ...............2
\n" ); document.write( "Multiply (1) by 2
\n" ); document.write( "Multiply (2) by 2 2/3
\n" ); document.write( "we get 2
\n" ); document.write( "5 1/3 x + -5 1/3 y = 200
\n" ); document.write( "5 1/3 x + 5 1/3 y = 267
\n" ); document.write( "10 2/3 x = 467
\n" ); document.write( "/ 10 2/3
\n" ); document.write( "x = 43 3/4 mph
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\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "2 2/3 x -2 2/3 y = 100
\n" ); document.write( "116 2/3 -2 2/3 -116 2/3 = 100
\n" ); document.write( "-2 2/3 y = 100
\n" ); document.write( "-2 2/3 y = -16 2/3 mph
\n" ); document.write( " y = 6 1/4
\n" ); document.write( "Boat speed 43 3/4 mph
\n" ); document.write( "stream 6 1/4 mph
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\n" ); document.write( "CHECK
\n" ); document.write( "x+y= 50
\n" ); document.write( "X-y= 37 1/2
\n" ); document.write( "100 / ( 43 3/4 + 6 1/4 )= 2
\n" ); document.write( "100 / ( 43 3/4 )- 6 1/4 = 2 2/3
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