document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007619>Question 1007619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A crystal ball with a diameter of 6 inches is being packaged for shipment. If the crystal ball is placed inside a circular cylinder with radius 3 inches and height 6 inches, how much volume will need to be filled with padding? (The volume of a sphere with radius r is 43&#960;r3, and the volume of a right circular cylinder with radius r and height is &#960;r2h.) Use \"pi\" for &#960;. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623537 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume of padding is the volume of the cylinder minus the volume of the sphere...so (remember radius is half the diameter)...<BR>\n" );
document.write( "V = (pi)r^2*h - (4/3)(pi)r^3<BR>\n" );
document.write( "V = (pi)(3^2)(6) - (4/3)(pi)(3^3)<BR>\n" );
document.write( "V = 54(pi) - 36(pi)<BR>\n" );
document.write( "V = 18(pi) cubic inches </SPAN>\n" );
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