document.write( "Question 1007682: In right triangleABC , the length of the hypotenuse is 25 and the lengths of the legs are x and 3x + 3. What is
\n" ); document.write( "the perimeter of the triangle? \n" ); document.write( "
Algebra.Com's Answer #623530 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "Using Pythagoras theorem
\n" ); document.write( "x^2+(3x+3)^2 = 625\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x^2+9x^2+18x +9 =625\r
\n" ); document.write( "\n" ); document.write( "10x^2+18x -616=0\r
\n" ); document.write( "\n" ); document.write( "/2
\n" ); document.write( "5x^2+9x-308=0\r
\n" ); document.write( "\n" ); document.write( "5x^2-35x+44x-308=0\r
\n" ); document.write( "\n" ); document.write( "5x(x-7)+44(x-7)=0\r
\n" ); document.write( "\n" ); document.write( "(5x+4)(x-7)=0\r
\n" ); document.write( "\n" ); document.write( "5x+4 = 0 OR x-7=0\r
\n" ); document.write( "\n" ); document.write( "x= -4/5 Or 7\r
\n" ); document.write( "\n" ); document.write( "x cannot be negative\r
\n" ); document.write( "\n" ); document.write( "Therefore x =7 \r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "x^2= 49
\n" ); document.write( "(3x+3)^2 = 576\r
\n" ); document.write( "\n" ); document.write( "576 + 49 = 625\r
\n" ); document.write( "\n" ); document.write( "x= 7
\n" ); document.write( "(3x+3)= 24\r
\n" ); document.write( "\n" ); document.write( "Hypotenuse = 25\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 7+24+25 = 56\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );