document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007676>Question 1007676</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find A, B, and C for the partial fraction decomposition.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+%284x%5E2%29-3x%2B7+%29+%2F+%28+%28x-1%29%28%28x%5E2%29+%2B+3%29+%29+ ALIGN=MIDDLE  ALT=\"+%28+%284x%5E2%29-3x%2B7+%29+%2F+%28+%28x-1%29%28%28x%5E2%29+%2B+3%29+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "So far I am able to get <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%28+A%2F%28x-1%29+%29+%2B+%28+%28Bx+%2B+C%29%2F%28x%5E2%2B3%29+%29+ ALIGN=MIDDLE  ALT=\"+%28+A%2F%28x-1%29+%29+%2B+%28+%28Bx+%2B+C%29%2F%28x%5E2%2B3%29+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623513 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find A, B, and C for the partial fraction decomposition.<BR>\n" );
document.write( " ( (4x^2)-3x+7 ) / ( (x-1)((x^2) + 3) )  \r<BR>\n" );
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document.write( "So far I am able to get::<BR>\n" );
document.write( "--------<BR>\n" );
document.write( " ( A/(x-1) ) + ( (Bx + C)/(x^2+3) )<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "= A(x^2+3) + (Bx+c)(x-1) / [(x-1)(x^2+3)]<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Equating the numerators you get::<BR>\n" );
document.write( "A(x^2) + 3A + Bx^2 + cx -Bx - c = 4x^2 - 3x + 7<BR>\n" );
document.write( "======<BR>\n" );
document.write( "(A+B)x^2 + (c-B)x + 3A - c = 4x^2 - 3x + 7<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equate the corresponding coefficients to get 3 equations::<BR>\n" );
document.write( "A + B = 4<BR>\n" );
document.write( "C - B = -3<BR>\n" );
document.write( "3A = 7<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "A = 7/3<BR>\n" );
document.write( "A+C = 1, So C = -4/3<BR>\n" );
document.write( "A + B = 4, So B = 4-7/3 = 5/3<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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