document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007677>Question 1007677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jacob and Isaac pull firewood on a sled with a mass of 60kg to the right across a snow covered field. Jacob pulls with a force of 30N and Isaac pulls with a force of 20N and there is a force of friction of 15N. <BR>\n" );
document.write( "1. What is the net force acting on the sled?<BR>\n" );
document.write( "2. What is the acceleration of the sled?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623507 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)  The net force is 30N + 20N - 15N = 35N to the right...friction almost always works in opposition to the motion...<BR>\n" );
document.write( "2)  Newton's Second Law gives a = F/m = 35N / 60kg = .583 m/s^2 </SPAN>\n" );
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