document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007572>Question 1007572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Father is 5 times as old as his son.In 18 years the father will twice as old as his son.How is the father at present? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623447 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623447\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let their ages NOW be f and s.  So we have<BR>\n" );
document.write( "f = 5s   and in 18 years<BR>\n" );
document.write( "f+18 = 2(s+18)<BR>\n" );
document.write( "f+18 = 2s + 36<BR>\n" );
document.write( "f = 2s + 18<BR>\n" );
document.write( "Now substitute the first into this second one and get<BR>\n" );
document.write( "5s = 2s + 18<BR>\n" );
document.write( "3s = 18<BR>\n" );
document.write( "s = 6 years old<BR>\n" );
document.write( "f is then 30 years old </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );