document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007494>Question 1007494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a men starts his journey by a car at 4.30 pm to cover a distance of 171 km moving at 12.5 m/s then at what time he will complete his journey. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623401 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623401\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since distance = rate * time, or d = rt, then <BR>\n" );
document.write( "t = d/r = 171 km / 12.5 m/s = 171000 m / 12.5 m/s = 13680 seconds<BR>\n" );
document.write( "This is 13680 / 60 = 228 minutes or 3 hours, 48 minutes.<BR>\n" );
document.write( "Add that to 4:30 pm and get<BR>\n" );
document.write( "8:18 pm </SPAN>\n" );
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