document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007275>Question 1007275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem: \r<BR>\n" );
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document.write( "A fish is being reeled in at a rate of 30 cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the line and the water changing when there is 8m of line out ? \r<BR>\n" );
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document.write( "fishing line = hypotenuse <BR>\n" );
document.write( "4m = height <BR>\n" );
document.write( "theta = angle opposite 4m and adjacent water and hypotenuse\r<BR>\n" );
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document.write( "Your help is always appreciated!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623398 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A fish is being reeled in at a rate of 30cm/s from a bridge that is 4m above the water. At what rate is the angle (in rads/s) between the line and the water changing when there is 8m of line out ? <BR>\n" );
document.write( "fishing line = hypotenuse <BR>\n" );
document.write( "4m= height <BR>\n" );
document.write( "theta= angle opposite 4m and adjacent water and hypotenuse <BR>\n" );
document.write( "Hypotenuse = c<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "Angle a = arcsin(4/c)<BR>\n" );
document.write( "Differentiate implicitly<BR>\n" );
document.write( "da/dt = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2Fsqrt%281+-+%284%2Fc%29%5E2%29%29%2A%28-4%2Fc%5E2%29%2A+%28dc%2Fdt%29 ALIGN=MIDDLE  ALT=\"%281%2Fsqrt%281+-+%284%2Fc%29%5E2%29%29%2A%28-4%2Fc%5E2%29%2A+%28dc%2Fdt%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "dc/dt = -0.3 m/sec<BR>\n" );
document.write( "da/dt = (1/sqrt(1 – 16/64))*(-4/64)*(-0.3)<BR>\n" );
document.write( "da/dt = (1/sqrt(3/4))*(1.2/64)<BR>\n" );
document.write( "= sqrt(3)/80 rad/sec<BR>\n" );
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