document.write( "Question 1007444: In a right triangle, a bisector of the right angle divides the hypotenuse in the ratio of 3:5. Determine the measure of the acute angles. \n" ); document.write( "
Algebra.Com's Answer #623388 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " In a right triangle, a bisector of the right angle divides the hypotenuse in the ratio of 3:5. Determine the measure of the acute angles. \r
\n" ); document.write( "\n" ); document.write( "let the acute angles be \"alpha\" and \"beta\"\r
\n" ); document.write( "\n" ); document.write( "if a bisector of the right angle divides the hypotenuse in the ratio of \"3%3A5\", then the measures of acute angles be \"alpha\" and \"beta\" will be in same ratio; so,\r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Fbeta=3%2F5\"\r
\n" ); document.write( "\n" ); document.write( "\"alpha=%283%2F5%29beta\"\r
\n" ); document.write( "\n" ); document.write( "since \"alpha%2Bbeta=90\", we have\r
\n" ); document.write( "\n" ); document.write( "\"%283%2F5%29beta%2Bbeta=90\"\r
\n" ); document.write( "\n" ); document.write( "\"%283%2F5%29beta%2B%285%2F5%29beta=90\"\r
\n" ); document.write( "\n" ); document.write( "\"%288%2F5%29beta=90\"
\n" ); document.write( "\"beta=90%2F%288%2F5%29\"
\n" ); document.write( "\"beta=450%2F8\"
\n" ); document.write( "\"highlight%28beta=56.25%29\"\r
\n" ); document.write( "\n" ); document.write( "now find \"alpha\"
\n" ); document.write( "\"alpha=%283%2F5%29beta\"
\n" ); document.write( "\"alpha=%283%2A56.25%29%2F5\"
\n" ); document.write( "\"alpha=3%2A11.25\"
\n" ); document.write( "\"highlight%28alpha=33.75%29\"\r
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