document.write( "Question 1007431: A=(1 0)
\n" ); document.write( " (0 2) \r
\n" ); document.write( "\n" ); document.write( "B=(0 1)
\n" ); document.write( " (1 0)\r
\n" ); document.write( "\n" ); document.write( "X=(a b)
\n" ); document.write( " (c d)
\n" ); document.write( "Find the value of a+b+c+d when AX=B\r
\n" ); document.write( "\n" ); document.write( "Please help me with solution\r
\n" ); document.write( "\n" ); document.write( "P.S the answer should be \"3/2\"\r
\n" ); document.write( "\n" ); document.write( "Thank you so much for your help!
\n" ); document.write( "

Algebra.Com's Answer #623386 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
this is just matrix multiplication, you multiply rows of A by columns of X to get elements of B
\n" ); document.write( "( 1 0 ) times ( a b )
\n" ); document.write( "( 0 2 ) ( c d )
\n" ); document.write( "*****************************
\n" ); document.write( "( a b ) equals ( 0 1 )
\n" ); document.write( "( 2c 2d ) ( 1 0 )
\n" ); document.write( "a = 0, b = 1, c = 1/2, d = 0
\n" ); document.write( "0 + 1 + (1/2) + 0 = (3/2)
\n" ); document.write( "
\n" ); document.write( "
\n" );