document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007446>Question 1007446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 108 cm. If the length is increased by 5 and the width is doubled. The perimeter becomes 182cm. Find it's dimension. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623385 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Here perimeter P = 2L + 2W = 108 or L + W = 54  or  L = 54 - W<BR>\n" );
document.write( "Then in the second case,<BR>\n" );
document.write( "2(L + 5) + 2(2W) = 182<BR>\n" );
document.write( "Substitute the first equation into this one and get<BR>\n" );
document.write( "2(54 - W + 5) + 4W = 182<BR>\n" );
document.write( "2(59 - W) + 4W = 182<BR>\n" );
document.write( "118 - 2W + 4W = 182<BR>\n" );
document.write( "2W + 118 = 182<BR>\n" );
document.write( "2W = 64<BR>\n" );
document.write( "W = 32 cm<BR>\n" );
document.write( "L = 54 - 32 = 22 cm </SPAN>\n" );
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