document.write( "Question 1007354: I need help solving (x^2 * y^3) * (x^-2 * y^-2), with ^ representing to the power to (Exponent) \n" ); document.write( "
Algebra.Com's Answer #623358 by Theo(13342) You can put this solution on YOUR website! the problem as you show it is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 * y^3) * (x^-2 * y^-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since they're all multiplications, you can remove the parentheses to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 * y^3 * x^-2 * y^-2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can use the associative law to regroup them as shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 * x^-2) * (y^3 * y^-2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 * x^-2 = x^(2-2) = x^0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y^3 * y^-2 = y^(3-2) = y^1 = y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your answer is y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the exponent property that allows this is\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^a * x^b = x^(a+b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when a = 2 and b = -2, this becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 * x^-2 = x^(2 + (-2)) which becomes x^(2-2) which becomes x^0 which is equal to 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "similarly, y^a + y^b = y^(a+b)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when a = 3 and b = -2, this becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y^3 * y^-2) = y^(3 + (-2)) which becomes y^(3-2) which becomes y^1 which is equal to y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "another exponent property that you could have used is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^-a = 1/x^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "also x^a / x^b = x^(a-b).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using this property, you get x^-2 = 1/x^2 and y^-2 = 1/y^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation of (x^2 * y^3) * (x^-2 * y^-2) becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 * y^3) * (1/x^2 * 1/y^2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "re-associate as before to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 * 1/x^2) * (y^3 * 1/y^2) which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^(2-2) * y^(3-2) which becomes x^0 * y^1 which becomes y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get the same answer either way.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |