document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1007049>Question 1007049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary has $3,500 in a savings account earning 4 1/2% annual interest that is compounded continuously. How much will be in the account at the end of 3 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #623335 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=623335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mary has $3,500 in a savings account earning 4 1/2% annual interest that is compounded continuously. How much will be in the account at the end of 3 years?<BR>\n" );
document.write( "Formula for continuous compounding: A=Pe^rt, P=initial investment, r=interest rate, A=amt after t-yrs\r<BR>\n" );
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document.write( "A=3500e^.005*3=$3552.90<BR>\n" );
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