document.write( "Question 1007371: The population N(t) (in millions) of India t years after 1985 may be approximated by the formula
\n" ); document.write( "N(t) = 766e^0.0182t.
\n" ); document.write( " When will the population reach 1.4 billion? (Round your answer to one decimal place.)
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Algebra.Com's Answer #623291 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "N(t) is the population in millions.
\n" ); document.write( "So if N(t) = 1, then we have 1 million people. If N(t) = 2, then we have 2 million, etc.
\n" ); document.write( "1.4 billion = 1400 million\r
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\n" ); document.write( "\n" ); document.write( "So if N(t) is in millions, then N(t) = 1400 represents 1.4 billion people. \r
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\n" ); document.write( "\n" ); document.write( "This means that we need to solve N(t) = 1400 for t \r
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\n" ); document.write( "\n" ); document.write( "\"N%28t%29+=+1400\"\r
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\n" ); document.write( "\n" ); document.write( "\"766e%5E%280.0182t%29+=+1400\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28766e%5E%280.0182t%29%29%2F766+=+1400%2F766\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%280.0182t%29+=+1400%2F766\"\r
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\n" ); document.write( "\n" ); document.write( "\"Ln%28e%5E%280.0182t%29%29+=+Ln%281400%2F766%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.0182t%2ALn%28e%29+=+Ln%281400%2F766%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.0182t%2A1+=+Ln%281400%2F766%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"0.0182t+=+Ln%281400%2F766%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F0.0182%29%2A0.0182t+=+%281%2F0.0182%29%2ALn%281400%2F766%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%281%2F0.0182%29%2ALn%281400%2F766%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+33.134359662789\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+33.1\"\r
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\n" ); document.write( "\n" ); document.write( "The population will reach 1.4 billion people after 33.1 years. This will happen between the years 2018 and 2019
\n" ); document.write( "Note: 1985+33 = 2018
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